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प्रश्न
The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
उत्तर
Given: Perimeter of one square = 40 m
Let length of square = a1
Then 4a1 = 40 m
⇒ a1 = 10 m
Area of square = a1 × a1
= 10 × 10
= 100 m2
Perimeter of second square = 96 m
Let length of square = a2
Then 4a2 = 96 m
⇒ a2 = 24 m
Area of square = a2 × a2
= 24 × 24
= 576 m2
Because, perimeter of another square equal in area to the sum of the first two squares.
Hence, area of another square = 100 + 576 = 676 m
Area of square = a3 × a3
676 = (a3)2
⇒ a3 = 26 m
Hence, perimeter = 4a3
= 4 × 26
= 104 m
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