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प्रश्न
factorise : 16(5x + 4)2 -9(3x - 2)2
योग
उत्तर
16(5x + 4)2 -9(3x - 2)2
= (4(5x + y))2 - (3(3x - 2))2
= [4 (5x + 4) - 3 (3x - 2)] [4(5x + 4) +3(3x - 2)]
.....[a2 - b2 = (a - b)(a + b)]
= (20x + 16 - 9x + 6)(20x + 16 + 9x - 6)
= (11x + 22)(29x + 10)
= 11 (x + 2)(29x + 10)
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Factorisation by Difference of Two Squares
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