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प्रश्न
factorise: 25(x - 2y)2 - 4
योग
उत्तर
25(x - 2y)2 - 4
= (5(x - 2y))2 - 22
= [5 (x - 2y) - 2] [5 (x - 2y) + 2] ...[a2 - b2 = (a - b)(a + b)]
= (5x - 10y - 2)(5x - 10y + 2)
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Factorisation by Difference of Two Squares
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