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प्रश्न
Factorise: a2 + 4a + 4 - b2
योग
उत्तर
a2 + 4a + 4 - b2
....[(a + b)2 = a2 + 2ab + b2]
....[a2 - b2 = (a + b)(a - b)]
= (a)2 + 2 × a × 2 + (2)2 - (b)2
= (a + 2)2 - (b)2
= (a + 2 + b) (a + 2 - b)
= (a + b + 2) (a - b + 2)
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Factorisation by Difference of Two Squares
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