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प्रश्न
Factorise: 25(a - 5b)2 - 4(a - 3b)2
योग
उत्तर
25(a - 5b)2 - 4(a - 3b)2
= [5 (a - 5b)]2 - [2(a - 3b)]2
= (5a - 25b)2 - (2a - 6b)2
= (5a - 25b + 2a - 6b)(5a - 25b - 2a + 6b)
.....[a2 - b2 = (a + b)(a - b)]
= (7a - 31b)(3a - 19b)
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Factorisation by Difference of Two Squares
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