Advertisements
Advertisements
प्रश्न
Factorise: a2 - b2 - 2b - 1
योग
उत्तर
a2 - b2 - 2b - 1
= a2 - (b2 + 2b + 1)
...[(a + b)2 = a2 + b2 + 2ab]
...[a2 - b2 = (a + b) (a - b)]
= (a)2 - (b + 1)2
= (a + b + 1)(a - b - 1)
shaalaa.com
Factorisation by Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise: 4x2 - 81y2
Factorise: (a+ 2b)2 - a2
Factorise: 1 - 25 (a+ b)2
Factorise: 49(x - y)2 -9(2x + y)2
Factorise: `(6 2/3)^2 - (2 1/3)^2`
Factorise: a2 + 4a + 4 - b2
factorise : a2 - (b - c)2
factorise : 16(5x + 4)2 -9(3x - 2)2
Factorise: 25(a - 5b)2 - 4(a - 3b)2
Factorise: 15(2x - y)2 - 16(2x - y) - 15
