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प्रश्न
Factorise: 1 - 25 (a+ b)2
योग
उत्तर
1 - 25 (a+ b)2
= (1)2 - [5(a+b)]2
= [1 + 5(a+b)] [1 - 5(a+b)]
= (1 + 5a + 5b) (1 - 5a - 5b)
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Factorisation by Difference of Two Squares
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