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प्रश्न
Factorise: 4(2a + b)2 - (a - b)2
योग
उत्तर
4(2a + b)2 - (a - b)2
= [2(2a + b)]2 - (a - b)2
= [2(2a + b) + a - b][2 (2a + b) -a + b]
= (4a + 2b + a - b)(4a + 2b - a + b)
= (5a + b)(3a + 3b)
= (5a + b) 3(a + b)
= 3 (5a + b) (a + b)
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Factorisation by Difference of Two Squares
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