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प्रश्न
Factorise : 4a2 - 49b2 + 2a - 7b
योग
उत्तर
4a2 - 49b2 + 2a - 7b
= [ ( 2a )2 - ( 7b )2] + [ 2a - 7b ]
= [ 2a - 7b ][ 2a + 7b ] + [ 2a - 7b ] [ ∵ a2 - b2 = ( a + b )( a - b ) ]
= [ 2a - 7b ][ 2a + 7b + 1 ]
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Method of Factorisation : Difference of Two Squares
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