Advertisements
Advertisements
प्रश्न
Factorise : a4 - 1
योग
उत्तर
a4 - 1
= ( a2 )2 - ( 1 )2
= ( a2 + 1 )( a2 - 1 ) [ ∵ a2 - b2 = ( a + b )( a - b )]
= ( a2 + 1 )[ (a)2 - (1)2 ]
= ( a2 + 1 )( a + 1 )( a - 1 )
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : a2 - (2a + 3b)2
Factorise : 50a3 - 2a
Factorise : 9(a - 2)2 - 16(a + 2)2
Factorise : 4a2 - 49b2 + 2a - 7b
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise:
(a2 - 1) (b2 - 1) + 4ab
Factorise the following by the difference of two squares:
x6 - 196
Factorise the following by the difference of two squares:
a(a - 1) - b(b - 1)
Factorise the following:
(2a - b)2 -9(3c - d)2
Factorise the following:
(a2 - b2)(c2 - d2) - 4abcd
