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प्रश्न
Factorise : a2 - (2a + 3b)2
योग
उत्तर
a2 - (2a + 3b)2
= a2 - ( 2a + 3b )2
= ( a - 2a - 3b )( a + 2a + 3b ) [ ∵ a2 - b2 = ( a + b )(a - b)]
= ( - a - 3b )( 3a + 3b )
= - 3( a + 3b )( a + b )
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Method of Factorisation : Difference of Two Squares
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