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प्रश्न
Factorise the following by the difference of two squares:
441 - 81y2
योग
उत्तर
441 - 81y2
= (21)2 - (9y)2
= (21 - 9y)(21 + 9y)
= 3(7 - 3y)3(7 + 3y)
= 9(7 - 3y)(7 + 3y).
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Method of Factorisation : Difference of Two Squares
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