Advertisements
Advertisements
प्रश्न
Factorise the following:
(x2 + y2 - z2)2 - 4x2y2
उत्तर
(x2 + y2 - z2)2 - 4x2y2
= (x2 + y2 - z2)2 - (2xy)2
= (x2 + y2 - z2 - 2xy)(x2 + y2 - z2 + 2xy)
= [(x2 + y2 - 2xy) - z2][(x2 + y2 + 2xy) - z2]
= [(x - y)2 - z2][(x + y)2 - z2]
= [(x - y - z)(x - y + z)][(x + y - z)(x + y + z)]
= (x - y - z)(x - y + z)(x + y - z)(x + y + z).
APPEARS IN
संबंधित प्रश्न
Factorise : 50a3 - 2a
Factorise : 9(a - 2)2 - 16(a + 2)2
Factorise : a3 + 2a2 - a - 2
Factorise : x4 + x2 + 1
Factorise : a2 - b2 - (a + b) 2
Factorise the following by the difference of two squares:
`"m"^2 - (1)/(9)"n"^2`
Factorise the following by the difference of two squares:
a(a - 1) - b(b - 1)
Factorise the following by the difference of two squares:
(x - 2y)2 -z2
Factorise the following:
b2 - 2bc + c2 - a2
Express each of the following as the difference of two squares:
(x2 - 2x + 3)(x2 + 2x + 3)