Advertisements
Advertisements
प्रश्न
Factorise : 50a3 - 2a
योग
उत्तर
50a3 - 2a
= 2a( 25a2 - 1 )
= 2a[ (5a)2 - (1)2 ]
= 2a( 5a + 1 )( 5a - 1 ) [ ∵ a2 - b2 = ( a + b )( a - b )]
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : 3a5 - 108a3
Factorise : 9(a - 2)2 - 16(a + 2)2
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise:
(a2 - 1) (b2 - 1) + 4ab
Factorise : (a2 + b2 - 4c2)2 - 4a2b2
Factorise : (a + b) 2 - a2 + b2
Factorise the following:
b2 - 2bc + c2 - a2
Factorise the following:
(x2 + y2 - z2)2 - 4x2y2
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
Express each of the following as the difference of two squares:
(x2 + 2x - 3) (x2 - 2x + 3)