Advertisements
Advertisements
प्रश्न
Factorise : x4 + x2 + 1
योग
उत्तर
x4 + x2 + 1
= (x2)2 + 2x2. 1 + (1)2 - x2
= ( x2 + 1 )2 - (x)2 [ ∵ a2 - b2 = ( a + b )( a - b )]
= ( x2 + 1 - x )( x2 + 1 + x )
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : 25a2 - 9b2
Factorise : a3 + 2a2 - a - 2
Factorise : 4xy - x2 - 4y2 + z2
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise the following by the difference of two squares:
x6 - 196
Factorise the following by the difference of two squares:
625 - b2
Factorise the following by the difference of two squares:
`"m"^2 - (1)/(9)"n"^2`
Factorise the following:
(x + y)3 - x - y
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
Express each of the following as the difference of two squares:
(x2 + 2x - 3) (x2 - 2x + 3)