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प्रश्न
Factorise the following:
(x + y)3 - x - y
योग
उत्तर
(x + y)3 - x - y
= (x + y)(x + y)2 - (x + y)
= (x + y)[(x + y)2 - 1]
= (x + y)[(x + y + 1)(x + y - 1)]
= (x + y)(x + y + 1)(x + y - 1).
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Method of Factorisation : Difference of Two Squares
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