Advertisements
Advertisements
प्रश्न
Factorise : 4xy - x2 - 4y2 + z2
योग
उत्तर
4xy - x2 - 4y2 + z2
= z2 - ( x2 + 4y2 - 4xy )
= z2 - ( x - 2y )2
= [ z - ( x - 2y )][ z + ( x - 2y )] [ ∵ a2 - b2 = ( a + b )( a - b )]
= [ z - x + 2y ][ z + x - 2y ]
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : a2 - (2a + 3b)2
Factorise : a4 - 1
Factorise : (a + b)3 - a - b
Factorise : a (a - 1) - b (b - 1)
Factorise : 9a2 + 3a - 8b - 64b2
Factorise the following by the difference of two squares:
a(a - 1) - b(b - 1)
Factorise the following:
b2 - 2bc + c2 - a2
Factorise the following:
(x2 + y2 - z2)2 - 4x2y2
Factorise the following:
4xy - x2 - 4y2 + z2
Express each of the following as the difference of two squares:
(x2 - 2x + 3)(x2 + 2x + 3)
