Advertisements
Advertisements
प्रश्न
Factorise : 4xy - x2 - 4y2 + z2
बेरीज
उत्तर
4xy - x2 - 4y2 + z2
= z2 - ( x2 + 4y2 - 4xy )
= z2 - ( x - 2y )2
= [ z - ( x - 2y )][ z + ( x - 2y )] [ ∵ a2 - b2 = ( a + b )( a - b )]
= [ z - x + 2y ][ z + x - 2y ]
shaalaa.com
Method of Factorisation : Difference of Two Squares
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise : 25a2 - 9b2
Factorise : a2 - 81 (b-c)2
Factorise : a3 + 2a2 - a - 2
Factorise : (a2 + b2 - 4c2)2 - 4a2b2
Factorise : (x2 + 4y2 - 9z2)2 - 16x2y2
Factorize : 9a2 - (a2 - 4) 2
Factorise the following by the difference of two squares:
441 - 81y2
Factorise the following by the difference of two squares:
16a4 - 81b4
Factorise the following:
4xy - x2 - 4y2 + z2
Express each of the following as the difference of two squares:
(x2 + 2x - 3) (x2 - 2x + 3)
