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प्रश्न
Factorise the following by the difference of two squares:
16a4 - 81b4
बेरीज
उत्तर
16a4 - 81b4
= (4a2)2 - (9b2)2
= (4a2 - 9b2)(4a2 + 9b2)
= [(2a)2 - (3b)2](4a2 + 9b2)
= [(2a - 3b)(2a + 3b)](4a2+ 9b2)
= (2a - 3b)(2a + 3b)(4a2 + 9b2).
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Method of Factorisation : Difference of Two Squares
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