Advertisements
Advertisements
प्रश्न
Factorise the following by the difference of two squares:
16a4 - 81b4
योग
उत्तर
16a4 - 81b4
= (4a2)2 - (9b2)2
= (4a2 - 9b2)(4a2 + 9b2)
= [(2a)2 - (3b)2](4a2 + 9b2)
= [(2a - 3b)(2a + 3b)](4a2+ 9b2)
= (2a - 3b)(2a + 3b)(4a2 + 9b2).
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : 25(2a - b)2 - 81b2
Factorise : 9(a - 2)2 - 16(a + 2)2
Factorise : a3 + 2a2 - a - 2
Factorise : (a + b) 2 - a2 + b2
Factorize : 9a2 - (a2 - 4) 2
Factorise : `x^2 + 1/x^2 - 11`
Factorise the following by the difference of two squares:
625 - b2
Factorise the following by the difference of two squares:
a(a - 1) - b(b - 1)
Factorise the following by the difference of two squares:
x2 + y2 - z2 - 2xy
Factorise the following:
b2 - 2bc + c2 - a2
