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प्रश्न
Factorise the following:
4xy - x2 - 4y2 + z2
योग
उत्तर
4xy - x2 - 4y2 + z2
= z2 - x2 - 4y2 + 4xy
= z2 - (x2 + 4y2 - 4xy)
= z2 - (x - 2y)2
= [z - (x - 2y)][z + (x - 2y)]
= (z - x + 2y)(z + x - 2y).
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Method of Factorisation : Difference of Two Squares
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