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प्रश्न
Factorise : `4x^2 + 1/(4x)^2 + 1`
योग
उत्तर
`4x^2 + 1/(4x)^2 + 1`
= `4x^2 + 1/(4x)^2 + 2 - 1`
= `4x^2 + 1/(4x)^2 + 2 xx 2x xx 1/(2x) - 1`
= `( 2x + 1/(2x) + 1)^2 - (1)^2`
= `( 2x + 1/(2x) + 1 )( 2x + 1/(2x) - 1 )`
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Method of Factorisation : Difference of Two Squares
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