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प्रश्न
Factorise : a2 - 81 (b-c)2
योग
उत्तर
a2 - 81 (b-c)2
= ( a )2 - [ 9( b - c ) ]2
= [ a - ( 9b - 9c )][ a + ( 9b - 9c )] [ ∵ a2 - b2 = ( a + b )( a - b )]
= ( a - 9b + 9c )( a + 9b - 9c )
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Method of Factorisation : Difference of Two Squares
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