Advertisements
Advertisements
प्रश्न
Factorise : 4a2 - (4b2 + 4bc + c2)
योग
उत्तर
4a2 - (4b2 + 4bc + c2)
= ( 2a )2 - ( 2b + c )2
= [ 2a - ( 2b + c )][ 2a + (2b + c )] [ ∵ a2 - b2 = ( a + b )( a - b )]
= [ 2a - 2b - c ][ 2a + 2b + c ]
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : a2 - 81 (b-c)2
Factorise : 4a2 - 12a + 9 - 49b2
Factorise : a2 + b2 - c2 - d2 + 2ab - 2cd
Factorise:
(a2 - 1) (b2 - 1) + 4ab
Factorize : 9a2 - (a2 - 4) 2
Factorise : 4x4 - x2 - 12x - 36
Factorise the following by the difference of two squares:
x2 + y2 - z2 - 2xy
Factorise the following:
9(a - b)2 - (a + b)2
Factorise the following:
b2 - 2bc + c2 - a2
Factorise the following:
(x2 + y2 - z2)2 - 4x2y2
