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प्रश्न
factorise: a2 - 23a -108
योग
उत्तर
a2 - 23a -108
= a2 - 27a + 4a - 108 ...[27 × 4 = 108 and 27 -4 = 23]
= a(a - 27) + 4(a - 27)
= (a - 27)(a + 4)
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Factorisation by Grouping
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