Advertisements
Advertisements
प्रश्न
Factorise : a6 + 27b3
योग
उत्तर
a6 + 27b3
= ( a2 )3 + ( 3b )3
= ( a2 + 3b )[ (a2)2 - a2 x 3b + (3b)2 ] [ ∵ a3 + b3 = ( a + b )( a2 - ab + b2 )]
= ( a2 + 3b )[ a4 - 3a2b + 9b2 ]
shaalaa.com
Method of Factorisation : the Sum Or Difference of Two Cubes
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise:
a3 - 27
Factorise : a3 + 0.064
Factorise: (x - y)3 - 8x3
Factorise:
a4 - 343a
Factorise:
`(8"a"^3)/27 - "b"^3/8`
Factorise : 2x3 + 54y3 - 4x - 12y
Factorise : 1029 - 3x3
Show that : 133 - 53 is divisible by 8
Show that : 353 + 273 is divisible by 62
Evaluate :
`[ 5.67 xx 5.67 xx 5.67 + 4.33 xx 4.33 xx 4.33 ]/[5.67 xx 5.67 - 5.67 xx 4.33 + 4.33 xx 4.33]`
