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Question
Factorise : a6 + 27b3
Sum
Solution
a6 + 27b3
= ( a2 )3 + ( 3b )3
= ( a2 + 3b )[ (a2)2 - a2 x 3b + (3b)2 ] [ ∵ a3 + b3 = ( a + b )( a2 - ab + b2 )]
= ( a2 + 3b )[ a4 - 3a2b + 9b2 ]
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Method of Factorisation : the Sum Or Difference of Two Cubes
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