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प्रश्न
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2ax + 1
योग
उत्तर
We have,
a2x2 + 2ax + 1
= (ax)2 + 2 · ax · 1 + (1)2
= (ax + 1)2
= (ax + 1)(ax + 1)
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अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
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