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प्रश्न
Factorise:
y3 − 27
योग
उत्तर
y3 − 27
y3 − 33
We know that,
a3 − b3 = (a − b) (a2 + ab + b2)
y3 − 33 = (y − 3) (y2 + y × 3 + 32)
= (y − 3) (y2 + 3y + 9)
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]
Simplify:
\[\frac{a^3 - 27}{5 a^2 - 16a + 3} \div \frac{a^2 + 3a + 9}{25 a^2 - 1}\]
Factorise:
x3 − 64y3
Factorise:
125y3 − 1
Simplify:
(a + b)3 − a3 − b3
Factorise: 27p3 - 125q3.
Factorise: 54p3 - 250q3.
Simplify: (a - b)3 - (a3 - b3)
Simplify: (2x + 3y)3 - (2x - 3y)3
Factorise the following:
27x3 – 8y3
