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Simplify: x2−5x−24(x+3)(x+8)×x2−64(x−8)2 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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प्रश्न

Simplify:

\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]

सरल रूप दीजिए

उत्तर

It is known that,

a2 − b= (a + b) (a − b)

a3 − b3 = (a − b)(a2 + ab + b2)

\[\  \frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\] 

\[ = \frac{x^2 - 8x + 3x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{\left( x \right)^2 - \left( 8 \right)^2}{\left( x - 8 \right)^2}\] 

\[ = \frac{x\left( x - 8 \right) + 3\left( x - 8 \right)}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{\left( x + 8 \right)\left( x - 8 \right)}{\left( x - 8 \right)\left( x - 8 \right)}\] 

\[ = \frac{\left( x + 3 \right)\left( x - 8 \right)}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{\left( x + 8 \right)\left( x - 8 \right)}{\left( x - 8 \right)\left( x - 8 \right)}\] 

= 1

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अध्याय 6: Factorisation of Algebraic expressions - Practice Set 6.4 [पृष्ठ ३३]

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बालभारती Mathematics [English] 8 Standard Maharashtra State Board
अध्याय 6 Factorisation of Algebraic expressions
Practice Set 6.4 | Q 4 | पृष्ठ ३३
बालभारती Integrated 8 Standard Part 2 [English Medium] Maharashtra State Board
अध्याय 3.1 Factorisation of Algebraic expressions
Practice Set 6.4 | Q 1. (4) | पृष्ठ ४८
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