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प्रश्न
Factorise:
x3 − 64y3
योग
उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
x3 − 64y3
= (x) − (4y)3
= (x − 4y)[(x)2 + (x) × (4y)]
= (x − 4y)(x2 + 16y2 + 4xy)
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
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