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प्रश्न
Factorise:
x3 − 64y3
बेरीज
उत्तर
It is known that,
a3 − b3 = (a − b)(a2 + ab + b2)
x3 − 64y3
= (x) − (4y)3
= (x − 4y)[(x)2 + (x) × (4y)]
= (x − 4y)(x2 + 16y2 + 4xy)
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Simplify:
\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]
Factorise:
y3 − 27
Factorise:
343a3 − 512b3
Factorise:
`16a^3 - 128/b^3`
Simplify:
(3a + 5b)3 − (3a − 5b)3
Simplify:
(a + b)3 − a3 − b3
Simplify:
p3 − (p + 1)3
Factorise: 27p3 - 125q3.
Factorise: 54p3 - 250q3.
Factorise the following:
a6 – 64
