हिंदी

Find n, if: (15-n)!(13-n)! = 12 - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Find n, if: `((15 - "n")!)/((13 - "n")!)` = 12

योग

उत्तर

`((15 - "n")!)/((13 - "n")!)` = 12

∴ `((15 - "n")(14 - "n")(13 - "n")!)/((13 - "n")!)` = 12

∴ (15 – n)(14 – n) = 12 = 4 × 3

∴ (15 – n)(14 – n) = (15 – 11)(14 – 11)

∴ n = 11.

shaalaa.com
Factorial Notation
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Permutations and Combination - Exercise 3.2 [पृष्ठ ४९]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 3 Permutations and Combination
Exercise 3.2 | Q 6. (ii) | पृष्ठ ४९

संबंधित प्रश्न

Evaluate: 8!


Evaluate: 10! – 6!


Compute: `(12!)/(6!)`


Compute: `(12/6)!`


Compute: (3 × 2)!


Compute: `(8!)/((6 - 4)!)`


Write in terms of factorial.

3 × 6 × 9 × 12 × 15


Write in terms of factorial.

6 × 7 × 8 × 9


Write in terms of factorial.

5 × 10 × 15 × 20


Evaluate : `("n"!)/("r"!("n" - "r")!)` for n = 12, r = 12


Evaluate : `("n"!)/("r"!("n" - "r")!)` for n = 15, r = 8


Find n, if `"n"/(8!) = 3/(6!) + (1!)/(4!)`


Find n, if `"n"/(6!) = 4/(8!) + 3/(6!)`


Find n, if `(1!)/("n"!) = (1!)/(4!) - 4/(5!)`


Find n, if (n + 1)! = 42 × (n – 1)!


Find n, if: `((17 - "n")!)/((14 - "n")!)` = 5!


Find n, if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 5)!)` = 5 : 3


Find n, if: `((2"n")!)/(7!(2"n" - 7)!) : ("n"!)/(4!("n" - 4)!)` = 24 : 1


Show that `("n"!)/("r"!("n" - "r")!) + ("n"!)/(("r" - 1)!("n" - "r" + 1)!) = (("n" + 1)!)/("r"!("n" - "r" + 1)!)`


Show that `(9!)/(3!6!) + (9!)/(4!5!) = (10!)/(4!6!)`


Simplify `((2"n" + 2)!)/((2"n")!)`


Simplify n[n! + (n – 1)!] + n2(n – 1)! + (n + 1)!


Simplify `("n" + 2)/("n"!) - (3"n" + 1)/(("n" + 1)!)`


In how many ways can 10 examination papers be arranged so that the best and the worst papers never come together?


Select the correct answer from the given alternatives.

In how many ways 4 boys and 3 girls can be seated in a row so that they are alternate


Eight white chairs and four black chairs are randomly placed in a row. The probability that no two black chairs are placed adjacently equals.


Find the number of integers greater than 7,000 that can be formed using the digits 4, 6, 7, 8, and 9, without repetition: ______


If `((11 - "n")!)/((10 - "n")!) = 9,`then n = ______.


Let Tn denote the number of triangles which can be formed using the vertices of a regular polygon of n sides. If Tn + 1 – Tn = 21, then n is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×