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प्रश्न
उत्तर
Slope of line PQ = `("y"_2 - "y" _1)/("x"_2 - "x"_1)`\
= `(5 - 1)/(6 - 8)`
= `4/-2`
Slope = -2
Also,Slope of line PQ = tan θ
tan θ = -2
θ = tan-1 (-2)
Inclination = tan -1(-2)
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संबंधित प्रश्न
Find the slope of the line passing through the points A(-2, 1) and B(0, 3).
Find the slope of the line parallel to AB if : A = (−2, 4) and B = (0, 6)
A(5, 4), B(−3, −2) and C(1, −8) are the vertices of a triangle ABC. Find:
- the slope of the altitude of AB,
- the slope of the median AD and
- the slope of the line parallel to AC.
The lines represented by 4x + 3y = 9 and px – 6y + 3 = 0 are parallel. Find the value of p.
Determine whether the following point is collinear.
A(–4, 4), \[K\left( - 2, \frac{5}{2} \right),\] N (4, –2)
Find the slope of a line, correct of two decimals, whose inclination is 60°
Find the slope and the y-intercept of the following line 3x + y = 7
Find the value, of k, if the line represented by kx – 5y + 4 = 0 and 4x – 2y + 5 = 0 are perpendicular to each other.
Determine whether the following points are collinear. A(–1, –1), B(0, 1), C(1, 3)
Given: Points A(–1, –1), B(0, 1) and C(1, 3)
Slope of line AB = `(square - square)/(square - square) = square/square` = 2
Slope of line BC = `(square - square)/(square - square) = square/square` = 2
Slope of line AB = Slope of line BC and B is the common point.
∴ Points A, B and C are collinear.
