Advertisements
Advertisements
Question
Solution
Slope of line PQ = `("y"_2 - "y" _1)/("x"_2 - "x"_1)`\
= `(5 - 1)/(6 - 8)`
= `4/-2`
Slope = -2
Also,Slope of line PQ = tan θ
tan θ = -2
θ = tan-1 (-2)
Inclination = tan -1(-2)
APPEARS IN
RELATED QUESTIONS
The line through P(5, 3) intersects y-axis at Q.
(1) Write the slope of the line.
(2) Write the equation of the line.
(3) Find the coordinates of Q.
Find the slope of the line perpendicular to AB if : A = (0, −5) and B = (−2, 4)
The line passing through (−4, −2) and (2, −3) is perpendicular to the line passing through (a, 5) and (2, −1). Find a.
Show that the points P(a, b + c), Q(b, c + a) and R(c, a + b) are collinear.
Angles made by the line with the positive direction of X–axis is given. Find the slope of these line.
60°
Show that points P(1, –2), Q(5, 2), R(3, –1), S(–1, –5) are the vertices of a parallelogram.
Find the slope of a line parallel to the given line 3x-2y = 5
Find the slope and the y-intercept of the following line 4y = 5x - 8
Find the slope of the line passing through the points A(6, -2) and B(–3, 4).
If the lines kx – y + 4 = 0 and 2y = 6x + 7 are perpendicular to each other, find the value of k.
