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Question
Show that the points P(a, b + c), Q(b, c + a) and R(c, a + b) are collinear.
Solution
Let ∴ P(a, b + c) = (x1, y1)
∴ Q(b, c + a) = (x2, y2)
∴ R(c, a + b) = (x3, y3)
The points P, Q, R will be collinear if slope of PQ and QR is the same.
Slope of PQ = `(y_2 - y_1)/(x_2 - x_1)`
= `(c + a - (b + c))/(b - a)`
=`(c + a - b - c)/(b - a)`
= `(a - b)/(b - a)`
= `(- (b - a))/(b - a)`
= –1
Slope of QR = `(y_3 - y_2)/(x_3 - x_2)`
= `((a + b) - (c + a))/(c - a)`
= `(a + b - c - a)/(c - b)`
= `(b - c)/(c - b)`
= `(- (c - b))/(c - b)`
= –1
Hence, the points P, Q, and R are collinear.
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