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प्रश्न
Find the centre and radius of the circle.
2x2 + 2y2 – x = 0
योग
उत्तर
2x2 + 2y2 – x = 0
= `"x"^2 + "y"^2 - "x"/2 = 0`
= `("x"^2 -"x"/2) + "y"^2 = 0`
= `("x"^2 - "x"/2 + 1/16) + "y"^2 = 1/16`
= `("x" - 1/4)^2 + "y"^2 = (1/4)^2`
Thus, the centre of the given circle is `(1/4, 0)` while its radius is `1/4`.
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