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Find the distance between the following pair of point. T(–3, 6), R(9, –10) - Geometry Mathematics 2

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प्रश्न

Find the distance between the following pair of point.

T(–3, 6), R(9, –10)

संख्यात्मक

उत्तर

T(–3, 6), R(9, –10)

Let T (x1, y1) and R (x2, y2) be the given points.
∴ x1 = −3, y1 = 6, x2 = 9, y2 = −10

\[\mathrm{d(T,R)}=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}\]

= \[\sqrt{\left[9-(-3)\right]^{2}+\left(-10-6\right)^{2}}\]

= \[\sqrt{\left(9+3\right)^{2}+\left(-10-6\right)^{2}}\]

= \[\sqrt{12^{2}+\left(-16\right)^{2}}\]

= \[\sqrt{144 + 256}\]

= \[\sqrt{400}\]

= 20

∴ d(T, R) = 20 units

∴ The distance between the points T and R 20 units.

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अध्याय 5: Co-ordinate Geometry - Practice Set 5.1 [पृष्ठ १०७]

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बालभारती Geometry (Mathematics 2) [English] 10 Standard SSC Maharashtra State Board
अध्याय 5 Co-ordinate Geometry
Practice Set 5.1 | Q 1.5 | पृष्ठ १०७

संबंधित प्रश्न

Prove that the points (–3, 0), (1, –3) and (4, 1) are the vertices of an isosceles right angled triangle. Find the area of this triangle


Find the coordinates of the centre of the circle passing through the points (0, 0), (–2, 1) and (–3, 2). Also, find its radius.


Determine if the points (1, 5), (2, 3) and (−2, −11) are collinear.


Find the point on the x-axis which is equidistant from (2, -5) and (-2, 9).


Find the values of x, y if the distances of the point (x, y) from (-3, 0)  as well as from (3, 0) are 4.


Prove that the points A(1, 7), B (4, 2), C(−1, −1) D (−4, 4) are the vertices of a square.


A(–8, 0), B(0, 16) and C(0, 0) are the vertices of a triangle ABC. Point P lies on AB and Q lies on AC such that AP : PB = 3 : 5 and AQ : QC = 3 : 5. Show that : PQ = `3/8` BC.


The long and short hands of a clock are 6 cm and 4 cm long respectively. Find the sum of the distances travelled by their tips in 24 hours. (Use π = 3.14) ?


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(1 , 3) and (3 , 9)


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(6 , 8)


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The length of line PQ is 10 units and the co-ordinates of P are (2, -3); calculate the co-ordinates of point Q, if its abscissa is 10.


Calculate the distance between A (5, -3) and B on the y-axis whose ordinate is 9.


Use distance formula to show that the points A(-1, 2), B(2, 5) and C(-5, -2) are collinear.


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Case Study -2

A hockey field is the playing surface for the game of hockey. Historically, the game was played on natural turf (grass) but nowadays it is predominantly played on an artificial turf.

It is rectangular in shape - 100 yards by 60 yards. Goals consist of two upright posts placed equidistant from the centre of the backline, joined at the top by a horizontal crossbar. The inner edges of the posts must be 3.66 metres (4 yards) apart, and the lower edge of the crossbar must be 2.14 metres (7 feet) above the ground.

Each team plays with 11 players on the field during the game including the goalie. Positions you might play include -

  • Forward: As shown by players A, B, C and D.
  • Midfielders: As shown by players E, F and G.
  • Fullbacks: As shown by players H, I and J.
  • Goalie: As shown by player K.

Using the picture of a hockey field below, answer the questions that follow:

The point on x axis equidistant from I and E is ______.


Find a point which is equidistant from the points A(–5, 4) and B(–1, 6)? How many such points are there?


Show that points A(–1, –1), B(0, 1), C(1, 3) are collinear.


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