हिंदी

Find the distance between the following pairs of point. W (-72,4), X (11, 4) - Geometry Mathematics 2

Advertisements
Advertisements

प्रश्न

Find the distance between the following pairs of point.

W `((- 7)/2 , 4)`, X (11, 4)

योग

उत्तर

Let the co-ordinates of point W are (x1, y1) and of point X are (x2, y2)

`((-7)/2,4)` = (x1, y1)

(11, 4) = (x2, y2)

d (W, X) = `sqrt((x_2-x_1)^2+(y_2-y_1)^2)`

= `sqrt((11-(-7/2))^2+(4-4)^2`

= `sqrt((11+7/2)^2+0)`

= `(11 + 7/2)`

= `11/1+7/2`

= `(22+7)/2`

= `29/2`

= 14.5

∴ Distance between points W and X is 14.5.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Co-ordinate Geometry - Practice Set 5.1 [पृष्ठ १०७]

APPEARS IN

बालभारती Geometry (Mathematics 2) [English] 10 Standard SSC Maharashtra State Board
अध्याय 5 Co-ordinate Geometry
Practice Set 5.1 | Q 1.6 | पृष्ठ १०७

संबंधित प्रश्न

If the opposite vertices of a square are (1, – 1) and (3, 4), find the coordinates of the remaining angular points.


Determine if the points (1, 5), (2, 3) and (−2, −11) are collinear.


Find the point on the x-axis which is equidistant from (2, -5) and (-2, 9).


Find the distance between the points

P(a + b,a - b)andQ(a -b,a + b)


Using the distance formula, show that the given points are collinear:

(6, 9), (0, 1) and (-6, -7)


Using the distance formula, show that the given points are collinear:

(-2, 5), (0,1) and (2, -3)


Find the distance between the following pair of points.

L(5, –8), M(–7, –3)


Find the value of y for which the distance between the points A (3, −1) and B (11, y) is 10 units.


Prove that the following set of point is collinear :

(4, -5),(1 , 1),(-2 , 7)


Prove that the points (7 , 10) , (-2 , 5) and (3 , -4) are vertices of an isosceles right angled triangle.


Find the distance between the following pairs of point:

`(sqrt(3)+1,1)` and `(0, sqrt(3))`


A point P lies on the x-axis and another point Q lies on the y-axis.
Write the abscissa of point Q.


The centre of a circle is (2x - 1, 3x + 1). Find x if the circle passes through (-3, -1) and the length of its diameter is 20 unit.


Find distance between point Q(3, – 7) and point R(3, 3)

Solution: Suppose Q(x1, y1) and point R(x2, y2)

x1 = 3, y1 = – 7 and x2 = 3, y2 = 3

Using distance formula,

d(Q, R) = `sqrt(square)`

∴ d(Q, R) = `sqrt(square - 100)`

∴ d(Q, R) =  `sqrt(square)`

∴ d(Q, R) = `square`


Find distance CD where C(– 3a, a), D(a, – 2a)


If the distance between the points (4, P) and (1, 0) is 5, then the value of p is ______.


The distance between the points A(0, 6) and B(0, –2) is ______.


Point P(0, 2) is the point of intersection of y-axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3).


Find the value of a, if the distance between the points A(–3, –14) and B(a, –5) is 9 units.


Find distance between points P(– 5, – 7) and Q(0, 3).

By distance formula,

PQ = `sqrt(square + (y_2 - y_1)^2`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(125)`

= `5sqrt(5)`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×