Advertisements
Advertisements
प्रश्न
If the distance between the points (4, P) and (1, 0) is 5, then the value of p is ______.
विकल्प
4 only
± 4
– 4 only
0
उत्तर
If the distance between the points (4, p) and (1, 0) is 5, then the value of p is ± 4.
Explanation:
According to the question,
The distance between the points (4, p) and (1, 0) = 5
d = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
i.e., `sqrt((1 - 4)^2 + (0 - "p")^2` = 5
⇒ `sqrt((-3)^2 + "p"^2)` = 5
⇒ `sqrt(9 + "p"^2)` = 5
On squaring both the sides, we get
9 + p2 = 25
⇒ p2 = 16
⇒ p = ± 4
Hence, the required value of p is ± 4.
APPEARS IN
संबंधित प्रश्न
Find the distance between the following pairs of points:
(a, b), (−a, −b)
Find the values of x, y if the distances of the point (x, y) from (-3, 0) as well as from (3, 0) are 4.
Find all possible values of x for which the distance between the points
A(x,-1) and B(5,3) is 5 units.
If P (x , y ) is equidistant from the points A (7,1) and B (3,5) find the relation between x and y
Find the distance between the following pair of point in the coordinate plane.
(1 , 3) and (3 , 9)
Find the distance of the following point from the origin :
(0 , 11)
Prove that the following set of point is collinear :
(4, -5),(1 , 1),(-2 , 7)
x (1,2),Y (3, -4) and z (5,-6) are the vertices of a triangle . Find the circumcentre and the circumradius of the triangle.
ABCD is a square . If the coordinates of A and C are (5 , 4) and (-1 , 6) ; find the coordinates of B and D.
Calculate the distance between A (5, -3) and B on the y-axis whose ordinate is 9.