Advertisements
Advertisements
प्रश्न
Using the distance formula, show that the given points are collinear:
(-2, 5), (0,1) and (2, -3)
उत्तर
Let A( -2,5) , B(0,1) and C (2, -3) be the give points. Then
`AB= sqrt((0+2)^2 +(1+5)^2 ) = sqrt((2)^2 +(-4)^2) = sqrt(20) = 2 sqrt(5) `units
`BC = sqrt((2-0)^2 + (-3-1)^2) = sqrt((2)^2+(-4)^2) = sqrt(20) = 2 sqrt(5)` units
`AC= sqrt((2+2)^2 +(-3-5)^2) = sqrt((4)^2 +(-8)^2) = sqrt(80) = 4sqrt(5) `units
`∴ AB +BC = (2 sqrt(5)+2 sqrt(5)) units = 4 sqrt(5) units = Ac`
Hence, the given points are collinear
APPEARS IN
संबंधित प्रश्न
Find the coordinates of the centre of the circle passing through the points (0, 0), (–2, 1) and (–3, 2). Also, find its radius.
If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible values of k?
Find the distance between the points
P(a sin ∝,a cos ∝ )and Q( acos ∝ ,- asin ∝)
Find all possible values of x for which the distance between the points
A(x,-1) and B(5,3) is 5 units.
Using the distance formula, show that the given points are collinear:
(1, -1), (5, 2) and (9, 5)
Prove that the points (0 , 0) , (3 , 2) , (7 , 7) and (4 , 5) are the vertices of a parallelogram.
Given A = (x + 2, -2) and B (11, 6). Find x if AB = 17.
The centre of a circle is (2x - 1, 3x + 1). Find x if the circle passes through (-3, -1) and the length of its diameter is 20 unit.
Seg OA is the radius of a circle with centre O. The coordinates of point A is (0, 2) then decide whether the point B(1, 2) is on the circle?
Points A(4, 3), B(6, 4), C(5, –6) and D(–3, 5) are the vertices of a parallelogram.