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प्रश्न
If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible values of k?
उत्तर
Consider the points A(4, k) and B(1, 0).
It is given that the distance AB is 5 units.
By distance formula, disance AB is as follows:
`AB = sqrt((4-1)^2 + (k - 0)^2)`
`=> 5 = sqrt(9 + (k)^2)`
`=> 25 = 9 + k^2`
`=> 16 = k^2`
`=> +- 4 = k`
Hence, value of ka are `+- 4`
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