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Question
If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible values of k?
Solution
Consider the points A(4, k) and B(1, 0).
It is given that the distance AB is 5 units.
By distance formula, disance AB is as follows:
`AB = sqrt((4-1)^2 + (k - 0)^2)`
`=> 5 = sqrt(9 + (k)^2)`
`=> 25 = 9 + k^2`
`=> 16 = k^2`
`=> +- 4 = k`
Hence, value of ka are `+- 4`
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