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प्रश्न
Find the equation of the following circles having the centre (3, 5) and radius 5 units.
उत्तर
Equation of the circle is (x – h)2 + (y – k)2 = r2
Centre (h, k) = (3, 5) and radius r = 5
∴ Equation of the circle is (x – 3)2 + (y – 5)2 = 52
⇒ x2 – 6x + 9 + y2 – 10y + 25 = 25
⇒ x2 + y2 – 6x – 10y + 9 = 0
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संबंधित प्रश्न
Find the equation of the tangent to the circle x2 + y2 – 4x + 4y – 8 = 0 at (-2, -2).
If (4, 1) is one extremity of a diameter of the circle x2 + y2 - 2x + 6y - 15 = 0 find the other extremity.
The centre of the circle x2 + y2 – 2x + 2y – 9 = 0 is:
If the circle touches the x-axis, y-axis, and the line x = 6 then the length of the diameter of the circle is:
Obtain the equation of the circle for which (3, 4) and (2, -7) are the ends of a diameter.
Determine whether the points (– 2, 1), (0, 0) and (– 4, – 3) lie outside, on or inside the circle x2 + y2 – 5x + 2y – 5 = 0
Find centre and radius of the following circles
x2 + (y + 2)2 = 0
Find centre and radius of the following circles
x2 + y2 – x + 2y – 3 = 0
Choose the correct alternative:
The length of the diameter of the circle which touches the x -axis at the point (1, 0) and passes through the point (2, 3)
Choose the correct alternative:
The equation of the normal to the circle x2 + y2 – 2x – 2y + 1 = 0 which is parallel to the line 2x + 4y = 3 is
