Advertisements
Advertisements
प्रश्न
Find the equation of the following circles having the centre (0,0) and radius 2 units
उत्तर
Equation of the circle when centre origin (0, 0) and radius r is x2 + y2 = r2
⇒ x2 + y2 = 22
⇒ x2 + y2 = 4
⇒ x2 + y2 – 4 = 0
APPEARS IN
संबंधित प्रश्न
Find the centre and radius of the circle
x2 + y2 = 16
Find the centre and radius of the circle.
(x + 2) (x – 5) + (y – 2) (y – 1) = 0
Find the Cartesian equation of the circle whose parametric equations are x = 3 cos θ, y = 3 sin θ, 0 ≤ θ ≤ 2π.
Find the equation of the tangent to the circle x2 + y2 – 4x + 4y – 8 = 0 at (-2, -2).
The centre of the circle x2 + y2 – 2x + 2y – 9 = 0 is:
If the centre of the circle is (-a, -b) and radius is `sqrt("a"^2 - "b"^2)` then the equation of circle is:
The equation of the circle with centre (3, -4) and touches the x-axis is:
Find the equation of the circles with centre (2, 3) and passing through the intersection of the lines 3x – 2y – 1 = 0 and 4x + y – 27 = 0
Find centre and radius of the following circles
x2 + y2 – x + 2y – 3 = 0
Choose the correct alternative:
The radius of the circle 3x2 + by2 + 4bx – 6by + b2 = 0 is
