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प्रश्न
If the centre of the circle is (-a, -b) and radius is `sqrt("a"^2 - "b"^2)` then the equation of circle is:
विकल्प
x2 + y2 + 2ax + 2by + 2b2 = 0
x2 + y2 + 2ax + 2by – 2b2 = 0
x2 + y2 – 2ax – 2by – 2b2 = 0
x2 + y2 – 2ax – 2by + 2b2 = 0
उत्तर
x2 + y2 + 2ax + 2by + 2b2 = 0
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