Advertisements
Advertisements
प्रश्न
The equation of the circle with centre on the x axis and passing through the origin is:
विकल्प
x2 – 2ax + y2 = 0
y2 – 2ay + x2 = 0
x2 + y2 = a2
x2 – 2ay + y2 = 0
उत्तर
x2 – 2ax + y2 = 0
APPEARS IN
संबंधित प्रश्न
Find the centre and radius of the circle
x2 + y2 – 22x – 4y + 25 = 0
Find the centre and radius of the circle.
(x + 2) (x – 5) + (y – 2) (y – 1) = 0
Find the equation of the circle passing through the points (0, 1), (4, 3) and (1, -1).
Find the equation of the circle having (4, 7) and (-2, 5) as the extremities of a diameter.
Find the equation of the tangent to the circle x2 + y2 – 4x + 4y – 8 = 0 at (-2, -2).
The length of the tangent from (4, 5) to the circle x2 + y2 = 16 is:
Find the equation of the circle with centre (2, −1) and passing through the point (3, 6) in standard form
If y = `2sqrt(2)x + "c"` is a tangent to the circle x2 + y2 = 16, find the value of c
Find the equation of the tangent and normal to the circle x2 + y2 – 6x + 6y – 8 = 0 at (2, 2)
Determine whether the points (– 2, 1), (0, 0) and (– 4, – 3) lie outside, on or inside the circle x2 + y2 – 5x + 2y – 5 = 0
