Advertisements
Advertisements
Question
The equation of the circle with centre on the x axis and passing through the origin is:
Options
x2 – 2ax + y2 = 0
y2 – 2ay + x2 = 0
x2 + y2 = a2
x2 – 2ay + y2 = 0
Solution
x2 – 2ax + y2 = 0
APPEARS IN
RELATED QUESTIONS
Find the equation of the following circles having the centre (3, 5) and radius 5 units.
Find the centre and radius of the circle
x2 + y2 = 16
Find the equation of the circle passing through the points (0, 1), (4, 3) and (1, -1).
Find the equation of the tangent to the circle x2 + y2 – 4x + 4y – 8 = 0 at (-2, -2).
If the perimeter of the circle is 8π units and centre is (2, 2) then the equation of the circle is:
If the circle touches the x-axis, y-axis, and the line x = 6 then the length of the diameter of the circle is:
If the equation 3x2 + (3 – p)xy + qy2 – 2px = 8pq represents a circle, find p and q. Also determine the centre and radius of the circle
Choose the correct alternative:
The circle x2 + y2 = 4x + 8y + 5 intersects the line 3x – 4y = m at two distinct points if
Choose the correct alternative:
The length of the diameter of the circle which touches the x -axis at the point (1, 0) and passes through the point (2, 3)
Choose the correct alternative:
If the normals of the parabola y2 = 4x drawn at the end points of its latus rectum are tangents to the circle (x – 3)2 + (y + 2)2 = r2, then the value of r2 is
