If the centre of the circle is (-a, -b) and radius is aba2-b2 then the equation of circle is: - Business Mathematics and Statistics

If the centre of the circle is (-a, -b) and radius is `sqrt("a"^2 - "b"^2)` then the equation of circle is:

MCQ

x² + y² + 2ax + 2by + 2b² = 0

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Circles

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Chapter 3: Analytical Geometry - Exercise 3.7 [Page 72]

Chapter 3 Analytical Geometry
Exercise 3.7 | Q 15 | Page 72

Find the equation of the tangent to the circle x² + y² – 4x + 4y – 8 = 0 at (-2, -2).

Determine whether the points P(1, 0), Q(2, 1) and R(2, 3) lie outside the circle, on the circle or inside the circle x² + y² – 4x – 6y + 9 = 0.

If (4, 1) is one extremity of a diameter of the circle x² + y² - 2x + 6y - 15 = 0 find the other extremity.

(1, -2) is the centre of the circle x² + y² + ax + by – 4 = 0, then its radius:

If the circle touches the x-axis, y-axis, and the line x = 6 then the length of the diameter of the circle is:

Obtain the equation of the circle for which (3, 4) and (2, -7) are the ends of a diameter.

Find the equation of the circle through the points (1, 0), (– 1, 0) and (0, 1)

If y = `2sqrt(2)x + "c"` is a tangent to the circle x² + y² = 16, find the value of c

Choose the correct alternative:

The radius of the circle passing through the points (6, 2) two of whose diameter are x + y = 6 and x + 2y = 4 is

Choose the correct alternative:

If the coordinates at one end of a diameter of the circle x² + y² – 8x – 4y + c = 0 are (11, 2) the coordinates of the other end are