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प्रश्न
Find the equation of the circle with centre (2, −1) and passing through the point (3, 6) in standard form
उत्तर
Centre = C = (2, −1)
Passing through = A = (3, 6)
So radius = CA
= `sqrt((2 - 3)^2 + (- 1 - 6)^2)`
= `sqrt(1 + 49)`
= `5sqrt(50)`
Now centre = (2, −1) and radius = `sqrt(50)`
So equation of the circle is
(i.e) (x – 2)2 + (y + 1)2 = `sqrt(50)^2`
⇒ (x – 2)2 + (y + 1)2 = 50
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